I feel like the rule should clarify what happens in the case of multiple dishes that would fit the criteria. right now it’s ambiguous imo. <s>(also it should totally be a free subway fare)</s>

(oh dang the html didn’t work)

this just feels clunky right now

The wording here is really confusing. I’m not sure what’s supposed to happen.

I think it’s saying that if a Customer makes a selection that’s worth $21+ (to the Truck, including all bonuses) and another selection exists that would be worth $25+ (but no more than $4 higher than the first price), they switch to that selection. And with Free Parking a Customer will just keep changing to options that are $1-$4 more expensive than the previous one, until they can no longer do so.

It does seem convoluted, and I may be misreading it.

I don’t think the choice is resolved with a loop, the way I understand it, applying this rule does not trigger another choice. The change is made once and that’s it. If there is no dish to make the switch they don’t, and if there is one, they switch once.

However, I agree that someone could build a Menu with two equal options to switch to and that would break it, so I am withdrawing in case this causes a bug/scam.