Proposal: Some patches
Open for 48 hours, passes 3-0.—Quirck
Adminned at 28 Jul 2012 15:34:32 UTC
Replace the text of the rule “feeding” with
At the start of every other day, beginning July 27th 2012, all Farmers having at least one Manul must feed their Manuls. A Farmer who has at least 2(M-1) CW, where M is the number of Manuls that Farmer has, loses 2(M-1) CW and has fed their Manuls for the day. Otherwise, they must automatically sell Manuls by repeatedly decreasing their Manul count by one and simultaneously increasing their CW by 6 CW, until the Farmer has N Manuls and at least 2(N-1) CW, at which point they lose 2(N-1) CW and have fed their Manuls.
In the rule “Housekeeping”, change
The default number of Manuls is 1.
to
The default number of Manuls is 0.
if possible.
In the rule “Breeding”, replace
If a Farmer has not taken this action during a Day, the default breeding action shall take place: at the end of that Day, the number of newborn Manuls is determined as above, and all the newborn Manuls are sold.
with
If a Farmer has not taken this action during a Day and at the end of the Day owns not less than two Manuls, the default breeding action shall take place: the number of his newborn Manuls is determined as above, and all the newborn Manuls are sold.
Throughout the ruleset, replace “Worker” with “Farmer”, “Workers” with “Farmers”.
Prevent losing -2 CW
Changing default to zero. Which Farmer has no Manuls, he shouldn’t be able to do anything except adding first Manul with an Amulet.
Prevent arguable default breeding with less than two Manuls exploiting DICE0 = 1 (why not zero, dunno)
Worker is remnant from the past.
quirck: he/him
Arr, missed :(
“If a Farmer has not taken this action during a Day and at the end of the Day owns not less than two Manuls, the default breeding action shall take place once at the end of that Day: the number of his newborn Manuls is determined as above, and all the newborn Manuls are sold.”