Saturday, February 27, 2010

Proposal: Tinkering with the Rules

Passes at 16-0. -Purplebeard

Adminned at 01 Mar 2010 01:46:01 UTC

In the “Commoner’s Economy” Rule, replace

an amount of Coal (a number defaulting to the median value among Commoners, or 50 if the median would be undefined), and amounts of

with

and amounts of Coal,

and replace

(numbers defaulting to the median value among Commoners, or 0 if the median would be undefined)

with

(numbers defaulting to the median values among Commoners, rounding up to an integer if necessary)

.

Throughout the Ruleset, replace any instances of “Inventors” with “Commoners”.

Now that resource amounts have been initialized (50 coal, 0 others), the median will always be defined, so we drop references to starting with 50 Coal and 0 of other Resources, and just treat all Resource initialization equally.  In the case of an even set of data, the median is sometimes a half-integer, so we have to specify how to round.  This fix will work regardless of whether Iron gets replaced by Copper, Wood gets dropped, or Cogs get added in the list of Resources due to certain pending proposals.

Comments

Put:

27-02-2010 20:15:22 UTC

imperial

Klisz:

27-02-2010 20:29:00 UTC

for  Though I’d personally prefer rounding down.

Oze:

27-02-2010 20:31:25 UTC

imperial

ais523:

27-02-2010 20:53:52 UTC

for Should be uncontroversial fixes.

redtara: they/them

27-02-2010 22:03:52 UTC

for

Josh: Imperator he/they

27-02-2010 22:43:27 UTC

for

Darknight: he/him

27-02-2010 23:32:52 UTC

for

Kevan: he/him

27-02-2010 23:54:28 UTC

for

digibomber:

28-02-2010 02:04:29 UTC

for You wouldn’t have to round medians.

Roujo: he/him

28-02-2010 03:36:56 UTC

for

Klisz:

28-02-2010 05:35:35 UTC

@digibomber: Yes, you would, because generating a median involves division. To create a median you add all the numbers together and divide by the number of numbers. Example: if the numbers are 2, 5, 17, and 27, you divide 51 (2+5+17+27) by 4, resulting in 12.75.

Kevan: he/him

28-02-2010 10:40:42 UTC

[Darth] No - the median is the value in the middle position of a sorted list. But if you’ve got an even number of elements, it would be the average of the two middle elements, so could be fractional. (The median of “2, 5, 17, 27” is actually “(5+17)/2”, which is 11. But the median of “2, 5, 18, 27” would be 11.5.)

Klisz:

28-02-2010 16:20:52 UTC

Ah, okay, I had gotten confused.

Oze:

28-02-2010 20:11:27 UTC

for

lordcooper:

28-02-2010 21:15:24 UTC

for

Qwazukee:

28-02-2010 23:36:03 UTC

for

hellzapoppin:

01-03-2010 07:42:58 UTC

for

Purplebeard:

01-03-2010 09:35:16 UTC

for